DP1#1996
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The Coin Change (HouseRobber.java)It seems there was a mix-up in the problem you were solving. You submitted a solution for "House Robber" instead of "Coin Change". Please ensure you are solving the correct problem. For the Coin Change problem, you need to find the fewest number of coins to make up a given amount. For the Coin Change problem, a common approach is to use dynamic programming where you create an array Your solution for House Robber is good, but it's important to double-check the problem statement before submitting. VERDICT: NEEDS_IMPROVEMENT House Robber (Sample.java)It seems there was a misunderstanding. The problem you solved is "Coin Change", but the problem you were assigned is "House Robber". These are two distinct problems. For "House Robber", you need to design a solution that maximizes the amount robbed without taking adjacent houses. Your solution for "Coin Change" is well-implemented with dynamic programming, and your comments are clear. However, for "House Robber", you should consider a different approach. The reference solution uses recursion with two choices at each house: rob the current house and skip the next, or skip the current house and move to the next. This can be optimized with memoization or dynamic programming to avoid exponential time complexity. For "House Robber", a common efficient solution uses dynamic programming where dp[i] represents the maximum amount that can be robbed up to the i-th house. The recurrence is: You can implement this with O(n) time and O(1) space by using two variables to store the previous two states. Please ensure you are solving the correct problem in the future. Double-check the problem statement before coding. VERDICT: NEEDS_IMPROVEMENT |
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