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19 changes: 19 additions & 0 deletions solution/BOJ_1715_카드_정렬하기/김지원.py
Original file line number Diff line number Diff line change
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import heapq

N = int(input())
card_deck = []
for _ in range(N):
heapq.heappush(card_deck, int(input()))


if len(card_deck) == 1: #1개일 경우 비교하지 않아도 된다
print(0)
else:
answer = 0
while len(card_deck) > 1: #1개일 경우 비교하지 않아도 된다
temp_1 = heapq.heappop(card_deck) #제일 작은 덱
temp_2 = heapq.heappop(card_deck) #두번째로 작은 덱
answer += temp_1 + temp_2 #현재 비교 횟수를 더해줌
heapq.heappush(card_deck, temp_1 + temp_2) #더한 덱을 다시 넣어줌

print(answer)