Added New Year and Hurry solution

Domains/CompetitiveProgramming/Programs/C++/NewYearAndHurry.cpp

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+/*
+Problem: New Year and Hurry
+Platform: Codeforces
+Problem Code: 750A
+Difficulty: Easy
+Link: https://codeforces.com/problemset/problem/750/A
+
+Limak is going to participate in a contest on the last day of the 2016. The contest will start at 20:00 and will last four hours, exactly until midnight. 
+There will be n problems, sorted by difficulty, i.e. problem 1 is the easiest and problem n is the hardest. Limak knows it will take him 5·i minutes to 
+solve the i-th problem.
+
+Limak's friends organize a New Year's Eve party and Limak wants to be there at midnight or earlier. He needs k minutes to get there from his house, where 
+he will participate in the contest first.
+
+How many problems can Limak solve if he wants to make it to the party?
+
+Input
+The only line of the input contains two integers n and k (1 ≤ n ≤ 10, 1 ≤ k ≤ 240) — the number of the problems in the contest and the number of minutes 
+Limak needs to get to the party from his house.
+
+Output
+Print one integer, denoting the maximum possible number of problems Limak can solve so that he could get to the party at midnight or earlier.
+
+Examples
+Input:
+3 222
+Output:
+2
+
+Input:
+4 190
+Output:
+4
+
+Input:
+7 1
+Output:
+7
+
+
+Approach:
+1. Find the total time availabel.
+2. Lineraly calculate time for every next question.
+3. When time for problems > time available, return last valid number of questions.
+
+Time Complexity: O(n)
+Space Complexity: O(1)
+
+Contributor: SamaKool
+*/
+
+#include<bits/stdc++.h>
+using namespace std; 
+
+int main(){
+    int n, k;
+    cin>>n;
+    cin>>k;
+    int t = 240 - k;
+    int ans = 0;
+    int i = 1;
+    for(i = 1; i <= n; i++){
+        if(ans + 5*i <= t){
+            ans += 5*i;
+        }
+        else {
+            i = i - 1;
+            break;
+        }
+        if(i == n) break;
+    }
+    cout<<i;
+    return 0;
+}