Skip to content
Open
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
2 changes: 1 addition & 1 deletion ptx/apex.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -83,7 +83,7 @@
<xi:include href="./chapter_app_of_int.ptx"/>

<xi:include href="./chapter_differential_equations.ptx"/>

<xi:include href="./chapter_sequences_series.ptx"/>

<xi:include href="./chapter_planar_curves.ptx"/>
Expand Down
2 changes: 1 addition & 1 deletion ptx/sec_FTC.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -129,7 +129,7 @@
<m>x \geq 1</m> is given by <m>A(x)=\frac12 (x)(2x)-\frac12 (1)(2)=x^2-1</m>.
</p>

<figure xml:id="fig_ftc1b" vshift="-2">
<figure xml:id="fig_ftc1b" vshift="-1">
<caption>The area of the shaded region is <m>F(x) = \int_1^x 2t\, dt</m></caption>
<image width="47%">
<shortdescription>
Expand Down
2 changes: 1 addition & 1 deletion ptx/sec_Modeling.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -42,7 +42,7 @@
\draw [firstcolor] (-1.5,0) node [text width=60pt,align=center] (a) { \centering The rate of change of the population};
\draw [firstcolor,-&gt;] (a) -- (.3,.7);

\draw [firstcolor] (2,.25) node [text width=60pt,align=center] (b) { \centering the population.};
\draw [firstcolor] (2,0) node [text width=60pt,align=center] (b) { \centering the\\ population.};
\draw [firstcolor,-&gt;] (b) -- (1.6,.8);

\draw [firstcolor] (.5,2) node [text width=32pt,align=center] (c) { \centering is};
Expand Down
23 changes: 12 additions & 11 deletions ptx/sec_int_comp_tests.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -513,25 +513,26 @@
Since the limit on the left side diverges to <m>\infty</m>,
we can say that <m>\lim\limits_{n \to \infty}\sum_{i=N}^n b_i</m> also diverges to <m>\infty</m>.
</p>
<aside vshift="2">
<p>
A sequence <m>\{a_n\}</m> is a <em>positive sequence</em>
if <m>a_n \gt 0</m> for all <m>n</m>.
</p>

<p>
Because of <xref ref="thm_series_behavior"/>,
any theorem that relies on a positive sequence still holds true when <m>a_n \gt 0</m> for all but a finite number of values of <m>n</m>.
<idx><h>sequence</h><h>positive</h></idx>
</p>
</aside>
</li>
</ol>
</p>
</proof>

</theorem>

<aside vshift="2">
<p>
A sequence <m>\{a_n\}</m> is a <em>positive sequence</em>
if <m>a_n \gt 0</m> for all <m>n</m>.
</p>

<p>
Because of <xref ref="thm_series_behavior"/>,
any theorem that relies on a positive sequence still holds true when <m>a_n \gt 0</m> for all but a finite number of values of <m>n</m>.
<idx><h>sequence</h><h>positive</h></idx>
</p>
</aside>

<figure xml:id="vid-seqseries-intcomp-comp-test" component="video" vshift="10">
<caption>Video presentation of <xref ref="thm_series_direct_compare"/></caption>
Expand Down
2 changes: 1 addition & 1 deletion ptx/sec_lhopitals_rule.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -814,7 +814,7 @@
</pg-code>
<statement>
<p>
<m>\lim\limits_{x\to 1} \frac{<var name="$fu"/> }{<var name="$fl"/>}</m>
<md>\lim\limits_{x\to 1} \frac{<var name="$fu"/> }{<var name="$fl"/>}</md>
</p>

<p>
Expand Down
6 changes: 3 additions & 3 deletions ptx/sec_riemann.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -794,13 +794,13 @@
\draw (1.5,1) node {$\displaystyle x_i = x_0 + i\Delta x$};

\draw [firstcolor] (1,0) node [text width=32pt,align=center] (a) { \centering starting\\[-5pt] value};
\draw [firstcolor,-&gt;] (a) -- (.95,.75);
\draw [firstcolor,-&gt;] (a) -- (1.25,.75);

\draw [firstcolor] (2,2.5) node [text width=120pt,align=center] (b) { \centering number of subintervals\\[-5pt] between $x_0$ and $x_i$};
\draw [firstcolor,-&gt;] (b) -- (1.95,1.25);
\draw [firstcolor,-&gt;] (b) -- (2.05,1.25);

\draw [firstcolor] (3,0) node [text width=60pt,align=center] (c) { \centering subinterval\\[-5pt] size};
\draw [firstcolor,-&gt;] (c) -- (2.75,.75);
\draw [firstcolor,-&gt;] (c) -- (2.45,.75);

\end{tikzpicture}

Expand Down
182 changes: 91 additions & 91 deletions ptx/sec_sequences.ptx
Original file line number Diff line number Diff line change
Expand Up @@ -733,7 +733,7 @@
</p>

<figure xml:id="fig_seq4c" vshift="-3">
<caption>Scatter plot for the sequence in <xref ref="item_ex_seq4_3"/></caption>
<caption>Scatter plot for the sequence in <xref ref="item_ex_seq4_3"/> of <xref ref="ex_seq4"/></caption>
<!-- START figures/fig_seq4c.tex -->
<image width="47%">
<shortdescription>A scatter plot showing a representative sample of points from the third sequence in this example.</shortdescription>
Expand Down Expand Up @@ -1514,7 +1514,7 @@

<p>
<ol>
<li>
<li xml:id="ex_seq7_1">
<p>
<md>
<mrow>a_{n+1}-a_n \amp = \frac{n+2}{n+1} - \frac{n+1}{n}</mrow>
Expand All @@ -1523,84 +1523,13 @@
<mrow>\amp \lt 0 \text{ for all \(n\). }</mrow>
</md>
Since <m>a_{n+1}-a_n\lt 0</m> for all <m>n</m>,
we conclude that the sequence is decreasing.
</p>
</li>

<li>
<p>
<md>
<mrow>a_{n+1}-a_n \amp = \frac{(n+1)^2+1}{n+2} - \frac{n^2+1}{n+1}</mrow>
<mrow>\amp = \frac{\big((n+1)^2+1\big)(n+1)- (n^2+1)(n+2)}{(n+1)(n+2)}</mrow>
<mrow>\amp = \frac{n^2+3n}{(n+1)(n+2)}</mrow>
<mrow>\amp \gt 0 \text{ for all \(n\). }</mrow>
</md>
Since <m>a_{n+1}-a_n\gt 0</m> for all <m>n</m>,
we conclude the sequence is increasing.
</p>
</li>

<li>
<p>
We can clearly see in <xref ref="fig_seq7c"/>,
where the sequence is plotted, that it is not monotonic.
However, it does seem that after the first 4 terms it is decreasing.
To understand why, perform the same analysis as done before:

<md>
<mrow>a_{n+1}-a_n \amp = \frac{(n+1)^2-9}{(n+1)^2-10(n+1)+26} - \frac{n^2-9}{n^2-10n+26}</mrow>
<mrow>\amp = \frac{n^2+2n-8}{n^2-8n+17}-\frac{n^2-9}{n^2-10n+26}</mrow>
<mrow>\amp = \frac{(n^2+2n-8)(n^2-10n+26)-(n^2-9)(n^2-8n+17)}{(n^2-8n+17)(n^2-10n+26)}</mrow>
<mrow>\amp = \frac{-10n^2+60n-55}{(n^2-8n+17)(n^2-10n+26)}</mrow>
</md>.
we conclude that the sequence is decreasing, illustrated in <xref ref="fig_seq7a"/>.
</p>

<p>
We want to know when this is greater than, or less than, 0.
The denominator is always positive,
therefore we are only concerned with the numerator.
For small values of <m>n</m>,
the numerator is positive.
As <m>n</m> grows large,
the numerator is dominated by <m>-10n^2</m>,
meaning the entire fraction will be negative;
<ie/>, for large enough <m>n</m>, <m>a_{n+1}-a_n \lt 0</m>.
Using the quadratic formula we can determine that the numerator is negative for <m>n\geq 5</m>.
In short, the sequence is simply not monotonic,
though it is useful to note that for <m>n\geq 5</m>,
the sequence is monotonically decreasing.
</p>
</li>

<li xml:id="ex_seq7_4">

<p>
Again, the plot in <xref ref="fig_seq7d"/>
shows that the sequence is not monotonic,
but it suggests that it is monotonically decreasing after the first term.
We perform the usual analysis to confirm this.
<md>
<mrow>a_{n+1}-a_n \amp = \frac{(n+1)^2}{(n+1)!} - \frac{n^2}{n!}</mrow>
<mrow>\amp = \frac{(n+1)^2-n^2(n+1)}{(n+1)!}</mrow>
<mrow>\amp = \frac{-n^3+2n+1}{(n+1)!}</mrow>
</md>
When <m>n=1</m>, the above expression is <m>\gt 0</m>;
for <m>n\geq 2</m>, the above expression is <m>\lt 0</m>.
Thus this sequence is not monotonic,
but it is monotonically decreasing after the first term.
</p>
</li>
</ol>
</p>

<figure xml:id="fig_seq7">
<caption>Plots of sequences in <xref ref="ex_seq7"/></caption>
<sbsgroup>
<sidebyside widths="47% 47%" valign="bottom" margins="0%">
<figure xml:id="fig_seq7a">
<caption/>
<figure xml:id="fig_seq7a" vshift="3">
<caption>Plot of the sequence in <xref ref="ex_seq7_1"/> of <xref ref="ex_seq7"/></caption>
<!-- START figures/fig_seq7a.tex -->
<image>
<image width="47%">
<shortdescription>Plot of the first sequence in this example. It is decreasing and bounded below.</shortdescription>
<description>
<p>
Expand Down Expand Up @@ -1631,11 +1560,24 @@
</image>
<!-- figures/fig_seq7a.tex END -->
</figure>
</li>

<li xml:id="ex_seq7_2">
<p>
<md>
<mrow>a_{n+1}-a_n \amp = \frac{(n+1)^2+1}{n+2} - \frac{n^2+1}{n+1}</mrow>
<mrow>\amp = \frac{\big((n+1)^2+1\big)(n+1)- (n^2+1)(n+2)}{(n+1)(n+2)}</mrow>
<mrow>\amp = \frac{n^2+3n}{(n+1)(n+2)}</mrow>
<mrow>\amp \gt 0 \text{ for all \(n\). }</mrow>
</md>
Since <m>a_{n+1}-a_n\gt 0</m> for all <m>n</m>,
we conclude the sequence is increasing, illustrated in <xref ref="fig_seq7b"/>.
</p>

<figure xml:id="fig_seq7b">
<caption/>
<figure xml:id="fig_seq7b" vshift="2">
<caption>Plot of the sequence in <xref ref="ex_seq7_2"/> of <xref ref="ex_seq7"/></caption>
<!-- START figures/fig_seq7b.tex -->
<image>
<image width="47%">
<shortdescription>Scatter plot for the second sequence in this example. It is increasing but not bounded.</shortdescription>
<description>
<p>
Expand Down Expand Up @@ -1667,13 +1609,43 @@
</image>
<!-- figures/fig_seq7b.tex END -->
</figure>
</sidebyside>
</li>

<li xml:id="ex_seq7_3">
<p>
We can clearly see in <xref ref="fig_seq7c"/>,
where the sequence is plotted, that it is not monotonic.
However, it does seem that after the first 4 terms it is decreasing.
To understand why, perform the same analysis as done before:

<md>
<mrow>a_{n+1}-a_n \amp = \frac{(n+1)^2-9}{(n+1)^2-10(n+1)+26} - \frac{n^2-9}{n^2-10n+26}</mrow>
<mrow>\amp = \frac{n^2+2n-8}{n^2-8n+17}-\frac{n^2-9}{n^2-10n+26}</mrow>
<mrow>\amp = \frac{(n^2+2n-8)(n^2-10n+26)-(n^2-9)(n^2-8n+17)}{(n^2-8n+17)(n^2-10n+26)}</mrow>
<mrow>\amp = \frac{-10n^2+60n-55}{(n^2-8n+17)(n^2-10n+26)}</mrow>
</md>.
</p>

<sidebyside widths="47% 47%" valign="bottom" margins="0%">
<figure xml:id="fig_seq7c">
<caption/>
<p>
We want to know when this is greater than, or less than, 0.
The denominator is always positive,
therefore we are only concerned with the numerator.
For small values of <m>n</m>,
the numerator is positive.
As <m>n</m> grows large,
the numerator is dominated by <m>-10n^2</m>,
meaning the entire fraction will be negative;
<ie/>, for large enough <m>n</m>, <m>a_{n+1}-a_n \lt 0</m>.
Using the quadratic formula we can determine that the numerator is negative for <m>n\geq 5</m>.
In short, the sequence is simply not monotonic,
though it is useful to note that for <m>n\geq 5</m>,
the sequence is monotonically decreasing.
</p>

<figure xml:id="fig_seq7c" vshift="3">
<caption>Plot of the sequence in <xref ref="ex_seq7_3"/> of <xref ref="ex_seq7"/></caption>
<!-- START figures/fig_seq7c.tex -->
<image>
<image width="47%">
<shortdescription>Scatter plot for the third sequence in this example. It is not monotonic.</shortdescription>
<description>
<p>
Expand Down Expand Up @@ -1710,12 +1682,32 @@
<!-- figures/fig_seq7c.tex END -->
</figure>

<figure xml:id="fig_seq7d">
<caption/>
</li>

<li xml:id="ex_seq7_4">

<p>
Again, the plot in <xref ref="ex_seq7_4"/> of <xref ref="fig_seq7d"/>
shows that the sequence is not monotonic,
but it suggests that it is monotonically decreasing after the first term.
We perform the usual analysis to confirm this.
<md>
<mrow>a_{n+1}-a_n \amp = \frac{(n+1)^2}{(n+1)!} - \frac{n^2}{n!}</mrow>
<mrow>\amp = \frac{(n+1)^2-n^2(n+1)}{(n+1)!}</mrow>
<mrow>\amp = \frac{-n^3+2n+1}{(n+1)!}</mrow>
</md>
When <m>n=1</m>, the above expression is <m>\gt 0</m>;
for <m>n\geq 2</m>, the above expression is <m>\lt 0</m>.
Thus this sequence is not monotonic,
but it is monotonically decreasing after the first term.
</p>

<figure xml:id="fig_seq7d" vshift="3">
<caption>Plot of the sequence in <xref ref="ex_seq7_4"/> of <xref ref="ex_seq7"/></caption>
<!-- <caption>A plot of <m>\{a_n\} = \{n^2/n!\}</m> in <xref ref="ex_seq7_4"/></caption> -->
<!-- Either all get captions, or none. The labels in each image make it clear enough?-->
<!-- START figures/fig_seq7d.tex -->
<image>
<image width="47%">
<shortdescription>Scatter plot for the last sequence in this example. It is not monotonic.</shortdescription>
<description>
<p>
Expand Down Expand Up @@ -1754,9 +1746,17 @@
</image>
<!-- figures/fig_seq7d.tex END -->
</figure>
</sidebyside>
</sbsgroup>
</figure>

</li>
</ol>
</p>







</solution>
<solution component="video" vshift="0">
<title>Video solution</title>
Expand Down
Loading