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Copy pathprojectEuler043.cpp
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85 lines (63 loc) · 1.76 KB
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/* Problem 43
Sub-string Divisibility
The number, 1406357289, is a 0 to 9 pandigital number because it is made
up of each of the digits 0 to 9 in some order, but it also has a rather
interesting sub-string divisibility property.
Let d1 be the 1st digit, d2 be the 2nd digit, and so on. In this way,
we note the following:
d2d3d4 = 406 is divisible by 2
d3d4d5 = 063 is divisible by 3
d4d5d6 = 635 is divisible by 5
d5d6d7 = 357 is divisible by 7
d6d7d8 = 572 is divisible by 11
d7d8d9 = 728 is divisible by 13
d8d9d10 = 289 is divisible by 17
Find the sum of all 0 to 9 pandigital numbers with this property.
*/
#include <algorithm>
#include <iomanip>
#include <iostream>
#include <string>
using namespace std;
int strToInt (string s) {
int result = 0;
for (int i = 0; i < s.length (); i++) {
result += int (s [i] - 48) * pow (10, s.length () - 1 - i);
}
return result;
}
double strToDouble (string s) {
double result = 0;
for (int i = 0; i < s.length (); i++) {
result += double (s [i] - 48) * pow (10, s.length () - 1 - i);
}
return result;
}
bool isDivisible (string s) {
int nums [7] = {2, 3, 5, 7, 11, 13, 17};
for (int i = 0; i < 7; i++) {
s.erase (s.begin ());
string s2 = s.substr (0, 3);
if (strToInt (s2) % nums [i] != 0) {
return false;
}
}
return true;
}
int main () {
double panSum = 0;
int digits [10] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
do {
string s = "";
if (digits [0] != 0) {
for (int i = 0; i < 10; i++) {
s += to_string (digits [i]);
}
if (isDivisible (s)) {
panSum += strToDouble (s);
}
}
} while (next_permutation (digits, digits + 10));
cout << setprecision (0) << fixed;
cout << panSum << endl;
}