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/* Problem 26
Reciprocal Cycles
A unit fraction contains 1 in the numerator. The decimal representation
of the unit fractions with denominators 2 to 10 are given:
1/2 = 0.5
1/3 = 0.(3)
1/4 = 0.25
1/5 = 0.2
1/6 = 0.1(6)
1/7 = 0.(142857)
1/8 = 0.125
1/9 = 0.(1)
1/10 = 0.1
Where 0.1(6) means 0.166666..., and has a 1-digit recurring cycle.
It can be seen that 1/7 has a 6-digit recurring cycle.
Find the value of d < 1000 for which 1/d contains the longest recurring
cycle in its decimal fraction part.
*/
#include <iostream>
using namespace std;
int GCD (int a, int b) {
if (b == 0) {
return a;
}
return GCD (b, a % b);
}
// See wolfram's page on multiplicative order
int multiplicativeOrder (int ten, int mod) {
if (GCD (ten, mod) != 1) {
return -1;
}
int result = 1;
int k = 1;
while (k < mod) {
result = (result * ten) % mod;
if (result == 1) {
return k;
}
k++;
}
return -1;
}
int main () {
int d = 1;
int longestCycle = 0;
for (int i = 1; i < 1000; i++) {
int m = multiplicativeOrder (10, i);
if (m > longestCycle) {
d = i;
longestCycle = m;
}
}
cout << d << endl;
cout << longestCycle << endl;
}