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63 lines (49 loc) · 1.38 KB
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/* Problem 12
Highly Divisible Triangular Number
The sequence of triangle numbers is generated by adding the natural numbers
So the 7th triangle number would be 1 + 2 + 3 + 4 + 5 + 6 + 7 = 28.
The first ten terms would be:
1, 3, 6, 10, 15, 21, 28, 36, 45, 55, ...
Let us list the factors of the first seven triangle numbers:
1: 1
3: 1,3
6: 1,2,3,6
10: 1,2,5,10
15: 1,3,5,15
21: 1,3,7,21
28: 1,2,4,7,14,28
We can see that 28 is the first triangle number to have over five divisors.
What is the value of the first triangle number to have over 500 divisors?
*/
#include <iomanip>
#include <iostream>
using namespace std;
int getNumDivisors (double num) {
int nDivisors = 0;
// If num is odd, skip it.
if (num / 2 != floor (num / 2)) {
return 0;
}
for (int i = 1; i <= int(num); i++) {
if (num / double(i) == floor (num / double(i))) {
nDivisors++;
}
}
// if (nDivisors > 150) {
// cout << num << " has " << nDivisors << " divisors." << endl;
// }
return nDivisors;
}
int main () {
int n = 0; // Number of terms in the sequence of triangle numbers
int numDivisors = 1;
double triNum = 0;
while (numDivisors < 500) {
n++;
int triNum_previous = triNum;
triNum = triNum_previous + n;
numDivisors = getNumDivisors (triNum);
}
cout << setprecision (0) << fixed;
cout << triNum << endl;
}