From cc56c0151d33014b83b8e5af617308e02d67ba5f Mon Sep 17 00:00:00 2001
From: Sibabalwe <102536140+Ngandana@users.noreply.github.com>
Date: Fri, 22 Nov 2024 09:42:50 +0200
Subject: [PATCH] Update questions(my answers).sql

---
 SQL Deep Dive/Having/questions.sql | 23 +++++++++++++++++++++--
 1 file changed, 21 insertions(+), 2 deletions(-)

diff --git a/SQL Deep Dive/Having/questions.sql b/SQL Deep Dive/Having/questions.sql
index 681ac93..7f50a88 100644
--- a/SQL Deep Dive/Having/questions.sql	
+++ b/SQL Deep Dive/Having/questions.sql	
@@ -3,18 +3,37 @@
 *  Show me all the employees, hired after 1991, that have had more than 2 titles
 *  Database: Employees
 */
-
+SELECT e.emp_no, count(t.title) as "amount of titles"
+FROM employees as e
+JOIN titles as t USING(emp_no)
+WHERE EXTRACT (YEAR FROM e.hire_date) > 1991
+GROUP BY e.emp_no
+HAVING count(t.title) > 2
+ORDER BY e.emp_no;
 
 
 /*
 *  Show me all the employees that have had more than 15 salary changes that work in the department development
 *  Database: Employees
 */
-
+SELECT e.emp_no, count(s.from_date) as "amount of raises"
+FROM employees as e
+JOIN salaries as s USING(emp_no)
+JOIN dept_emp AS de USING(emp_no)
+WHERE de.dept_no = 'd005'
+GROUP BY e.emp_no
+HAVING count(s.from_date) > 15
+ORDER BY e.emp_no;
 
 
 /*
 *  Show me all the employees that have worked for multiple departments
 *  Database: Employees
 */
+SELECT e.emp_no, count(de.dept_no) as "worked for # departments"
+FROM employees as e
+JOIN dept_emp AS de USING(emp_no)
+GROUP BY e.emp_no
+HAVING count(de.dept_no) > 1
+ORDER BY e.emp_no;