Python/string at master · ZhangWilly/Python · GitHub

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2018/03/20

字串(string)資料型態及其運算

string1 = "I love you"

---------replace()取代--------------
string1.replace("love","hate")

---------join()--------------
'_'.join("Dragon")
'x'.join("Dragon")

-------split()---------------
string1.split()

#string2 = 'x'.join("Dragon")
#string2.split(sep='x')

string1.upper()
string1.swapcase()

###有空白==>去除空白#############
string11 = "   I love you  "
string11.strip()


---擴充版凱薩加密及暴力破解----------------------------------------------------------

#!/usr/bin/env python3

alpha = 'abcdefghijklmnopqrstuvwxyz'
num = '0123456789'
alnum = alpha + num

ctext = '7sj-ighm-742q3w4t'

def rotate(s, num):
    new1 = ''
    for c in s:
        if c in alnum:
            new1 += alnum[(alnum.index(c) + num) % 36]
        else:
            new1 += c
    return new1

for x in range(36):
    print("{}".format(rotate(ctext, x)))


====================
#!/usr/bin/env python3
import string

alphabet =  string.ascii_lowercase + string.ascii_uppercase + string.digits

ctext = "7sj-ighm-742q3w4t"

def shift(n):
    message = ""
    for index, char in enumerate(ctext):
        if char == "-":
            message += char
        else:
            message += alphabet[(alphabet.index(ctext[index])+n)%len(alphabet)]
    return message.upper()

for i in range(len(alphabet)):
    message = shift(i)
    if "RC3" in message:
        print(message)

------------------------------------------------------------------
a='cvqAeqacLtqazEigwiXobxrCrtuiTzahfFreqc{bnjrKwgk83kgd43j85ePgb_e_rwqr7fvbmHjklo3tews_hmkogooyf0vbnk0ii87Drfgh_n kiwutfb0ghk9ro987k5tfb_hjiouo087ptfcv}'

a=a[3:]
flag = ''
for x in range(0,len(a),1):
    if x%5==0:
        flag+=a[x]
print flag
------------------------------------------------------------------


re模組與正規表達法(NeXT)