From c7f96a38b9d987aee07c189f59d2c56f9c78a2e8 Mon Sep 17 00:00:00 2001
From: Asilbek <77490263+Asilbek-MR@users.noreply.github.com>
Date: Sat, 16 Dec 2023 09:35:22 +0500
Subject: [PATCH] Update 156.md

2390. Removing Stars From a String
author: Bahodirov Asilbek
---
 solutions/156.md | 46 ++++++++++++++++++++++++++++++++++++++++------
 1 file changed, 40 insertions(+), 6 deletions(-)

diff --git a/solutions/156.md b/solutions/156.md
index 3dc9580..cc2b642 100644
--- a/solutions/156.md
+++ b/solutions/156.md
@@ -1,16 +1,42 @@
 # [name_of_problem_in_leetcode](link_to_problem_in_leetcode)
-
+2390. Removing Stars From a String
 **Difficulty:** :green_circle: Easy| :yellow_circle: Medium| :red_circle: Hard
 
-problem_here
+You are given a string s, which contains stars *.
+
+In one operation, you can:
+
+Choose a star in s.
+Remove the closest non-star character to its left, as well as remove the star itself.
+Return the string after all stars have been removed.
+
+Note:
+
+The input will be generated such that the operation is always possible.
+It can be shown that the resulting string will always be unique.
 
 ## Examples:
 
-examples_here
+Example 1:
+
+Input: s = "leet**cod*e"
+Output: "lecoe"
+Explanation: Performing the removals from left to right:
+- The closest character to the 1st star is 't' in "leet**cod*e". s becomes "lee*cod*e".
+- The closest character to the 2nd star is 'e' in "lee*cod*e". s becomes "lecod*e".
+- The closest character to the 3rd star is 'd' in "lecod*e". s becomes "lecoe".
+There are no more stars, so we return "lecoe".
+Example 2:
+
+Input: s = "erase*****"
+Output: ""
+Explanation: The entire string is removed, so we return an empty string.
 
 ## Constraints:
 
-contraints_here
+1 <= s.length <= 105
+s consists of lowercase English letters and stars *.
+The operation above can be performed on s.
 
 ## Follow up:
 
@@ -19,9 +45,17 @@ follow_if_any_here
 
 ## Solutions
 
-### Name of solution 
+EASY & SIMPLE approach for problem solution
 
-```python
+```
+def removeStars(self, s: str) -> str:
+        ans=[]
+        for i in s:
+            if i=='*':
+                ans.pop()
+            else:
+                ans+=[i]
+        return "".join(ans)
 
 ```