From a9a22249a642aa475e030f43d03b5df0431effa8 Mon Sep 17 00:00:00 2001
From: Asilbek <77490263+Asilbek-MR@users.noreply.github.com>
Date: Sat, 16 Dec 2023 09:30:50 +0500
Subject: [PATCH] Update 155.md

Bahodirov Asilbek
---
 solutions/155.md | 33 ++++++++++++++++++++++++++++-----
 1 file changed, 28 insertions(+), 5 deletions(-)

diff --git a/solutions/155.md b/solutions/155.md
index 3dc9580..1a5b5ac 100644
--- a/solutions/155.md
+++ b/solutions/155.md
@@ -1,17 +1,30 @@
 # [name_of_problem_in_leetcode](link_to_problem_in_leetcode)
-
+1475. Final Prices With a Special Discount in a Shop
 **Difficulty:** :green_circle: Easy| :yellow_circle: Medium| :red_circle: Hard
 
 problem_here
+You are given an integer array prices where prices[i] is the price of the ith item in a shop.
 
-## Examples:
+There is a special discount for items in the shop. If you buy the ith item, then you will receive a discount equivalent to prices[j] where j is the minimum index such that j > i and prices[j] <= prices[i]. Otherwise, you will not receive any discount at all.
 
+Return an integer array answer where answer[i] is the final price you will pay for the ith item of the shop, considering the special discount.
+## Examples:
+Example 1:
+
+Input: prices = [8,4,6,2,3]
+Output: [4,2,4,2,3]
+Explanation: 
+For item 0 with price[0]=8 you will receive a discount equivalent to prices[1]=4, therefore, the final price you will pay is 8 - 4 = 4.
+For item 1 with price[1]=4 you will receive a discount equivalent to prices[3]=2, therefore, the final price you will pay is 4 - 2 = 2.
+For item 2 with price[2]=6 you will receive a discount equivalent to prices[3]=2, therefore, the final price you will pay is 6 - 2 = 4.
+For items 3 and 4 you will not receive any discount at all.
 examples_here
 
 ## Constraints:
 
 contraints_here
-
+1 <= prices.length <= 500
+1 <= prices[i] <= 1000
 ## Follow up:
 
 follow_if_any_here
@@ -20,8 +33,18 @@ follow_if_any_here
 ## Solutions
 
 ### Name of solution 
-
-```python
+iterator solution
+```def finalPrices(self, prices: List[int]) -> List[int]:
+        l = len(prices)
+        result = []
+        for i in range(l):
+            for j in range(1,l):
+                if j > i and prices[i] >= prices[j]:
+                    result.append(prices[i]-prices[j])
+                    break
+            else:
+                result.append(prices[i])
+        return result
 
 ```