Initialize a qubit to |0> and apply HZH gate should be equivalent to applying the X gate directly. The resulting state is |1> with phase=0. The current implementation carries a phase of 1.16 $\pi$. While the global phase technically doesn't matter, this is a bit confusing.
Initialize a qubit to |0> and apply$\pi$ . While the global phase technically doesn't matter, this is a bit confusing.
HZHgate should be equivalent to applying theXgate directly. The resulting state is |1> with phase=0. The current implementation carries a phase of 1.16